如题 那位蝈蝈知道的 请教~~~~~~~~~~~~~~

5分频，奇数分频都可以类似这么做,只需要改div1和div2的参数。div1为奇数分频除2的余数。采用上升延和下降延分别触发不同波形，最后叠加的方式产生奇数分频。
module divfreq(clk, clk1x, rst, clk1xpose, clk1xnege, coutpose, coutnege);
input clk;
input rst;
output clk1x;
output clk1xpose;
output clk1xnege;
output[2:0] coutpose;
output[2:0] coutnege;
reg clk1xpose;
reg clk1xnege;
reg[2:0] coutpose;
reg[2:0] coutnege;
parameter div1 = 2 , div2 = 4;  // div1 ＝ 5 / 2, div2 = 5 - 1
assign clk1x = clk1xpose | clk1xnege;
always@(posedge clk or negedge rst)
begin
  if(!rst)
 
    clk1xpose = 0;

  else if(coutpose == div1)
    clk1xpose = ~clk1xpose;
  else if(coutpose == div2)
    clk1xpose = ~clk1xpose;
  else
    clk1xpose = clk1xpose;
end
always@(negedge clk or negedge rst)
begin
  if(!rst)
 
    clk1xnege = 0;

  else if(coutnege == div1)
  clk1xnege = ~clk1xnege;
  else if(coutnege == div2)
  clk1xnege = ~clk1xnege;
  else
  clk1xnege = clk1xnege;
end
always@(posedge clk or negedge rst)
begin
  if(!rst)
  coutpose = 0;
  else if(coutpose == div2)
  coutpose = 0;
  else
  coutpose = coutpose + 1;
end
always@(negedge clk or negedge rst)
begin
  if(!rst)
  coutnege = 0;
  else if(coutnege == div2)
  coutnege = 0;
  else
  coutnege = coutnege + 1;
end
endmodule