Binary codes   poj1147
Time Limit:1000MS Memory Limit:65536K
Total Submit:1695 Accepted:626

Description

Consider a binary string (b1…bN) with N binary digits. Given such a string, the matrix of Figure 1 is formed from the rotated versions of the string.

  b1   b2 … bN-1 bN

  b2   b3 … bN   b1

  …

  bN-1 bN … bN-3 bN-2

  bN   b1 … bN-2 bN-1



  Figure 1. The rotated matrix

Then rows of the matrix are sorted in alphabetical order, where ‘0’ is before ‘1’. You are to write a program which, given the last column of the sorted matrix, finds the first row of the sorted matrix.

As an example, consider the string (00110). The sorted matrix is

  0 0 0 1 1

  0 0 1 1 0

  0 1 1 0 0

  1 0 0 0 1

  1 1 0 0 0

and the corresponding last column is (1 0 0 1 0). Given this last column your program should determine the first row, which is (0 0 0 1 1).

Input

The first line contains one integer N ≤ 3000, the number of binary digits in the binary string. The second line contains N integers, the binary digits in the last column from top to bottom.

Output

The first line contains N integers: the binary digits in the first row from left to right.

Sample Input

5
1 0 0 1 0

Sample Output

0 0 0 1 1

Source
IOI 2001 (back-up task)


[ 此贴被kangtalc在2007-04-16 12:28重新编辑 ]

我自己解决加浮云否？

当，，！！！
是从小到大排列的，哪来的问题。。。

嘿嘿，再给你一次机会吧，我其实已经搞定了。。。

到poj去提，你就知道对不对了。。。

比赛完了我来公布答案，版主先不要慌加FY给楼上...

把compile error 的错误贴出来给我。。。

我看见kiwiy过了。
楼楼上的再加油。。

Quote:

引用第30楼hhbhhb于2007-04-16 12:16发表的:
汗。。
数下有几个1，，然后全放到最后就可以了。。

hhb，这不应该是你的水平吧。。。。