错误是:
D:\C++\Noname4.cpp(11) : error C2660: 'match' : function does not take 2 parameters
D:\C++\Noname4.cpp(20) : error C2061: syntax error : identifier 'c'

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#include <stdio.h>

int count;

int main()
{
   char s[80],ch,* p, * match();

   gets(s);
   ch=getchar();
   p=match(ch,s);
   if(p)
   printf("%s%d\n",p,(count+1));
   else
       printf("no match found\n");
   return 0;
}


char * match(c,s)

{    
  char c, * s;

  count = 0;
  while (c!=s[count]&&s[count]!='\0')
      count++;
  if (s[count])
      return(&s[count]);
  return (0);

}

char *match(c,s)//应该要写c,s类型
match函数里面的c会覆盖你传的参数
没必要用count全局变量
个人愚见 不知道对不对 仅做参考

#include <stdio.h>
int count;

int main()
{
  char s[80],ch,* p, * match();
  gets(s);
  ch=getchar();
  p=match(ch,s);
  if(p)
  printf("%s%d\n",p,(count+1));
  else
    printf("no match found\n");
  return 0;
}


char * match(c,s)
char c, * s;
{  

count = 0;
while (c!=s[count]&&s[count]!='\0')
    count++;
if (s[count])
    return(&s[count]);
return (0);

}